Thread: Swap 2 words by pointers

hii
i need to swap 2 words by pointers
example

Code:

char *arr[]={"father","mother",NULL};

i tried to do like this :
but i know that char variable can't hold a word . what to do in place
of temp??

Code:

char *p1,*p2;
char temp;
temp=*arr;
*p1=*(arr+1);
*p2=temp;

Thank you.

http://www.eskimo.com/~scs/cclass/notes/top.html

Take a look around

You only need one pointer to preform a swap of two elements. What you want to do is to assign the value of one of the elements of the array to the temp pointer (which would be a char *temp), next, move the one you haven't refernced yet to the other location, then move temp back to that one.

IE:

Code:

char *a, *b, *temp;
//some init of a and b
temp = b;
b = a;
a = temp;
//done.