Thread: what is wrong?

i have written the code below:

Code:

#include<stdio.h>
void copy1(float a[],float b[],int c);
void copy2(float *d,float *c,int a);
int main(void)
{
    int a;
    float *b;
    static float rain[12]=
    {10.2,8.1,6.8,4.2,1.5,2.6,2.6,6.4,5.8,4.5,1.1,5.9};
    static float copy1[12]=
    {0,0,0,0,0,0,0,0,0,0,0,0};
    static float copy2[12]=
     {0,0,0,0,0,0,0,0,0,0,0,0};
   copy1(rain,copy1,6);
   copy2(rain,copy2,5);
   b=copy1;
   for (a=0;a<12;a++)
   
     printf("%4.1f",*(b+a));   
   
   
    system("pause");
    return 0;
}
void copy1(float a[],float b[],int c)
{
     int d;
     for (d=0;d<c;d++)
       b[d]=a[d];
     
}
void copy2(float *d,float *c,int a)
{
     int b;
     for (b=0;b<a;b++)
      (c+b)=*(d+b);
}

but after i have compiled it, I got the error saying "the called object is not a function" for copy1 and copy2, and "invalid value in assignment" for the last statement (c+b)=*(d+b); why is it so?

this has already been answered go to link below
http://cboard.cprogramming.com/showthread.php?t=87167

You have a function named copy1() and an array named copy1 that is local to main(). In your code, the compiler can't necessarily work out what you intend. Rename one of them. Similarly for copy2.

Within your copy2() function, the expression (c+b) is a pointer to float (the address of the b'th element of array c), and *(d+b) is a float (the value of the b'th element of array d). It is not possible to assign one directly to the other as they are different types. You probably intended "*(c+b)=*(d+b)"