Thread: Initialising everything in an array as 0

I want to initialise everything as zero, however my array is declared like this:

Code:

int test[x] = {0};

where x is a non zero positive int, but I get the error message:

58 C:\Documents and Settings\jb\My Documents\a.c variable-sized object may not be initialized
58 C:\Documents and Settings\jb\My Documents\a.c [Warning] excess elements in array initializer
58 C:\Documents and Settings\jb\My Documents\a.c [Warning] (near initialization for `test')

However when i declare it using:

Code:

int test[5] = {0};

it works fine, any ideas?

Thanks

Originally Posted by Wiretron

I want to initialise everything as zero, however my array is declared like this:

Code:

int test[x] = {0};

where x is a non zero positive int, but I get the error message:

58 C:\Documents and Settings\jb\My Documents\a.c variable-sized object may not be initialized
58 C:\Documents and Settings\jb\My Documents\a.c [Warning] excess elements in array initializer
58 C:\Documents and Settings\jb\My Documents\a.c [Warning] (near initialization for `test')

However when i declare it using:

Code:

int test[5] = {0};

it works fine, any ideas?

Thanks

Your problem description is inconsistent. If you replace x with 5 (a non zero positive int) then the line that supposedly doesn't work is the same as the one that does. Please correct your question.

Oh I see how your question is wrong. x is not a non-zero positive int. It is in fact as written - a variable of type int that has been assigned a non-zero, positive value.
You cannot do this when declaring an array.