Need an easier way to do Array addition.

[1BadRbt]

I know this program works but is there a way to shorten the code rather than run a sum for each row and column and get to accomplish the display I have accomplished?

#include <stdio.h>
#define ROWS 5
#define COLS 5

 int main()
{
 int x,y;
 int sumrow0, sumrow1, sumrow2, sumrow3, sumrow4;
 int sumcol0, sumcol1, sumcol2, sumcol3, sumcol4;
 
 int val[ROWS][COLS]={8,3,9,0,10,
                      3,5,17,1,1,
                      2,8,6,23,1,
                      15,7,3,2,9,
                      6,14,2,6,0};
 for (x=0; x<ROWS; x++)
 {
     printf("\n");
     for (y=0; y<COLS; y++)
     printf("%5d", val[x][y]);
     }
     
 sumrow0 = val[0][0]+val[0][1]+val[0][2]+val[0][3]+val[0][4];
 sumrow1 = val[1][0]+val[1][1]+val[1][2]+val[1][3]+val[1][4];
 sumrow2 = val[2][0]+val[2][1]+val[2][2]+val[2][3]+val[3][4];
 sumrow3 = val[3][0]+val[3][1]+val[3][2]+val[3][3]+val[3][4];
 sumrow4 = val[4][0]+val[4][1]+val[4][2]+val[4][3]+val[4][4];
 
 sumcol0 = val[0][0]+val[1][0]+val[2][0]+val[3][0]+val[4][0];
 sumcol1 = val[0][1]+val[1][1]+val[2][1]+val[3][1]+val[4][1];
 sumcol2 = val[0][2]+val[1][2]+val[2][2]+val[3][2]+val[4][2];
 sumcol3 = val[0][3]+val[1][3]+val[2][3]+val[3][3]+val[4][3];
 sumcol4 = val[0][4]+val[1][4]+val[2][4]+val[3][4]+val[4][4];
 
 printf("\nRow totals: %5d %2d %2d %2d %2d\n", sumrow0, sumrow1, sumrow2, sumrow3, sumrow4);
 printf("Column Totals: %2d %2d %2d %2d %2d", sumcol0, sumcol1, sumcol2, sumcol3, sumcol4); 
     return 0;
     }

[Salem]

int sumrow[5];

Then use a for loop.

[1BadRbt]

can you show me an example I already turned in the assignment cvause that sloppy crapola I put up fulfilled the assignment.

Just curious I guess since it is 2:45am I may be a lot confused.

[spoon!]

int sumrow[5] = {0}, sumcol[5] = {0};

for (x=0; x<ROWS; x++)
  for (y=0; y<COLS; y++) {
    sumrow[x] += val[x][y];
    sumcol[y] += val[x][y];
  }