Thread: I am stuck at the last line

Code:

#include <stdio.h>
#define size 3
void show_array(int ar[],int n);
void mult_array(int mult,int ar[],int n);

int main(void)
{
  static int dip[size]={1, 2, 3};
  printf("the original dip:\n");
  show_array(dip,size);
  mult_array(2,dip,size);
  printf("the array after:\n");
  show_array(dip,size);
  system("pause");
  return 0;
}
void show_array(int ar[],int n)
{
     int i;
     for(i=0;i<n;i++)
      printf("%8d",ar[i]);
     putchar('\n');
}
void mult_array(int mult,int ar[],int n)
{
     int i;
     for (i=0;i<n;i++)
     *(ar++)*=mult;
 }

the last statement is to multiply every element in dip[] by 2 and put it back, I tried to change it to (*ar)++*=mult, I expected that it will only increase the value which the pointer "ar" is pointing to. but it does not work and I also get an error from the compiler, can somebody help me? thanks

I can get the result if I use "ar[i]*=mult;" can you tell me why? the result will be assigned to ar[i], but this is a value inside the array, can it be assigned to that?