function error

[jms318]

This is the program

A parking garage charges $2 for minimum fee to park up to 3 hours and then a $.50 per hour charge after the 3rd hour. write a program that calculates and prints the parking charge for each of # customer. Result should be printed in tabular format. the program should use the function calculateCharges to determine the charge for each customer.

here is my code but i get some compile errors and i do not see where there is a mistake

#include <stdio.h>

double calculateCharges (double hours, double charge);

int main()
{
	
	int cars;
	double totalHours = 0;
	double totalCharge = 0;


	printf ("Please enter the number of cars parked for the day:\n");
	scanf  ("%d", &cars);

	if (cars >= 1){		

	printf ("Car\tHours\tCharge\n");
	printf ("%d\t%.1f\t%.2f\n", cars, calculateCharges(hours, charge));
	totalHours = totalHours + hours;
	totalCharge = totalCharge + charge;
	cars--;
	}

	if (cars == 0){

		printf ("Total\t%.1f\t%.2f\n", totalHours, totalCharge);
	}

	
	

	return (0);
}

double calculateCharges (double hours, double charge)
{
	double minRate = 2.00;
	double rate = 0.50;

	printf ("please enter cars total hours:");
	scanf  ("%.2f", &hours);

	if (hours < 3) {
		charge = minRate;
	}

	else {
		charge = minRate + (rate * (hours -3));
	}

	return;
}

here is my compiler errors

-------------------Configuration: parking - Win32 Debug--------------------
Compiling...
parking.c
C:\C Files\Chapter_5\parking\parking.c(19) : error C2065: 'hours' : undeclared identifier
C:\C Files\Chapter_5\parking\parking.c(19) : error C2065: 'charge' : undeclared identifier
C:\C Files\Chapter_5\parking\parking.c(52) : warning C4033: 'calculateCharges' must return a value
Error executing cl.exe.

parking.obj - 2 error(s), 1 warning(s)

thanks,
joe

[jms318]

ok i've played around with my code and here is the new code without any errors

#include <stdio.h>

double calculateCharges (double charge);

int main()
{
	
	int cars;
	double charge = 0;
	double hours = 0;
	double totalHours = 0;
	double totalCharge = 0;


	printf ("Please enter the number of cars parked for the day:\n");
	scanf  ("%d", &cars);

	if (cars >= 1){	
	
		

	printf ("Car\tHours\tCharge\n");
	printf ("%d\t%.1f\t%.2f\n", cars, calculateCharges(hours, charge));
	totalHours = totalHours + hours;
	totalCharge = totalCharge + charge;
	cars--;
	}

	if (cars == 0){

		printf ("Total\t%.1f\t%.2f\n", totalHours, totalCharge);
	}

	
	

	return (0);
}

double calculateCharges (double charge)
{
	double minRate = 2.00;
	double rate = 0.50;
	double hours;

	printf ("please enter cars total hours:");
		scanf  ("%.2f", &hours);

	

	if (hours < 3) {
		charge = minRate;
	}

	else {
		charge = minRate + (rate * (hours -3));
	}

	return charge;
}

now i'm susposed to have a tabulated foramt display something like this if say i had only 2 cars park for the day.

cars hours charge
1 2 2.00
2 5.5 4.50
total 7.5 6.50

all i get is this

Please enter the number of cars parked for the day:
2
Car Hours Charge
please enter cars total hours:2
2 2.0 0.00
Press any key to continue

[ssharish2005]

totalHours = totalHours + hours;
	totalCharge = totalCharge + charge;

Variables undeclared. you got declare that some where in your main. By looking a your code. I guess u wanted to do some value by reference things??

return charge;

your calculateCharges function should return a value. In your case it should return charge.

ssharish2005

[ssharish2005]

calculateCharges(hours, charge));

what's this. Dint you get a compiler error. U got to send two arguments to your function.

and for reading more than one car details, u got use a loop and array to achive that. Array is to hold more than one car details.

ssharish2005

[jms318]

ssharish2005
amazingly I didn't get one

i think i understand what your saying about an array but how would one write this in order to keep all the values i need to print the correct tabulated format after all pertian information is entered?????

thanks,
joe

[ssharish2005]

#include<stdio.h>

int main()
{
    printf("%-10d%-10d%-10d\n",10,10000,10000);
    printf("%-10d%-10d%-10d",100000,10,1000);
    
    getchar();
    return 0;
}

/*my output
10        10000     10000
100000    10        1000
*/

hope this helps you

ssharish2005