I am new to C, and am having a lot of trouble with the scanf function.
I am using it to read a single character like this:
scanf("%c",&character);
this works fine in the main function, but in any other function, it always skips this line. it executes the line above and after it, without prompting the user for input. Can anyone tell me what might be happening here?
thx.
What happens when you type a letter? You press enter. So that's actually two characters you've entered, right? Well, you'll need to take care of that enter key there in your read. Or better yet, never use scanf, and avoid this sort of thing. (Read: FAQ )
Quzah.
Hope is the first step on the road to disappointment.
I used to get really frustrated with scanf because the formatting it provides is nice, but when used with getch (posibly for some flow control), it is hectic, and as a beginner I am still slow to catch on to this kind of thing. Perhaps it is better to implement the functionality that scanf provides with functions I design myself. Otherwise, working with cin in C++ (although I know I'm in a C-programming forum) also works out pretty nicely.
I think in the other function, you don't use "*" to make change.
Example:
Code:void change(char*character) { printf("Add a character: "); scanf("%c",&character); }
The above code, while a seperate issue as my understanding of the OP's issue goes, is incorrect. It would be:Originally Posted by vddking2
The & would be omitted in this case, since character is already a pointer.Code:void change( char*character ) { printf("Add a character: "); scanf("%c",character); }
Quzah.
Hope is the first step on the road to disappointment.
Thanks- the problem was, as quzah said, that i did not realize enter was read also.
