Thread: A data structure i created with a function

Code:

#include <stdio.h>

struct
{
char Name[];
char address[];
float SS[];
int age[];
char gender[];
char statues[];
}

void sentence( char struct array[], char buffer[], int X);

main(void)
{
struct info employees[10];
int i=0,num;
printf("How many employees you wish to log?\n");
scanf("%d",num);

if(num > 10){
printf("Error only up to 10\n");
printf("How many employees you wish to log?\n");
scanf("%d",num); }

printf("what are the employees names?\n");

sentence(employees.Name[],num);

printf("What are the addresses?\n");

sentence(employees.address[],num);

printf("What is there sex?\n");

sentence(employees.gender[],num);

printf("is the employees marry or single?\n");

sentence(employees.statues[],num);

for(i=0, i != num, ++ i) 
{
printf("What is employees ages?\n");
scanf("%d",&employees.age[60]);
printf("What is employees social security\n");
scanf("%f",&employees.ss[10]);
}


}


 void sentence(Char struct array[], char  buffer[],int x)
{
  int i, z;
char letter;

for(i = 0; i != x; ++ i) {
do 
{
 letter = getchar();
 array[i].buffer[z] = letter;
++ z;
} while(letter != '\n');

array[i].buffer[z-1] = '\0';

printf("%s",array[i].buffer);

}

i have a problem bring a structure into a function...

Originally Posted by Dave_Sinkula

You have a problem with basic syntax.

Code:

struct
{
char Name[];
char address[];
float SS[];
int age[];
char gender[];
char statues[];
}

These arrays need sizes, and the struct ought to have a name and a closing semicolon.

Code:

void sentence( char struct array[], char buffer[], int X);

What's that?

Code:

   sentence(employees.Name[],num);

If you intend to specify an element, then specify an element. If you mean the whole array, then omit the []. If you mean an element of employees, move the brackets.

Code:

main(void)

Wake up and smell 1990.

No is not the program is that i wanted to know a good example of putting a structure element into an function..my program is just a draft in other words(soo i left alot of things out)

Much of Dave's advice is still relevant though because before you can pass a structure to a function, the structure needs to be declared properly and usually with a name. Then you can pass it to a function just like you would any other data type.

well thank you for the help. i'll see to it i keep alternating my program....

i still have problems with it...i want to input multiple employee's information but i mess up with calling structures into a function....

Code:

#include <stdio.h>

struct info
{
char Name;
char address;
float SS;
int age;
char gender;
char statues;
};

void sentence(char array[]);
void clear_buffer(void);

int main(void)
{
    struct info employees[10];
    int i=0,num;

    printf("How many employees you wish to log?\n");
    scanf("%d",&num); /* u need to give the address of num variable hence &num*/
    clear_buffer();
    
    if(num > 10)
    {
        while( num < 10 ) {
        printf("Error only up to 10\n");
        printf("How many employees you wish to log?\n");
        scanf("%d",&num); /* u need to give the address of num variable hence &num*/
 		     }
    }
    for( i = 0; i > num; ++ i)
    printf("what are the employees names?\n");
    sentence(employees[i].Name); /* Look at your function prototype it dosn't take 3 parameter */

    printf("What are the addresses?\n");
    sentence(employees[i].address);
    
    printf("What is there sex?\n");
    sentence(employees[i].gender);

    printf("is the employees marry or single?\n");
    sentence(employees[i].statues);
    
    printf("What is employees ages?\n");
    scanf("%d",&employees[i].age);
        
    printf("What is employees social security\n");
    scanf("%f",&employees[i].SS);

   
    return 0;
}


void sentence(char array[])
{
  int  z=0;
  char letter,*sentence_pointer,  buffer[90];
  
    do 
    {    
        letter = getchar();
        buffer[z] = letter;
        ++ z;
    } while(letter != '\n');
    
    buffer[z-1] = '\0';
    sentence_pointer =&buffer;
    array[] <- sentence_pointer;
}

void clear_buffer(void)
{
    int ch;
    while((ch=getchar())!='\n');
}

basically it want a char to be inputted in but i don't want to type cast seen it will mess up with my for...

Code:

/* This is a functon which is been used to read the data from the user and place that
in the data element of the struct

for example:
    sentence(employees[i].Name);  // You send the char array to the function to get the data
                                    and place that in the char array which u have sent in this 
                                    case its employee[i].Name

When you send the string to the function its using a method called call by reference. which meains 
what every u change the value in the fucntion it reflects the original value. Where u dont need to 
return the value back to the main.
*/

void sentence(char array[])
{
  int  z=0;   // count variable
  char letter;   // Letter used to hold char which is read from the user
  
    do 
    {    
        letter = getchar();   // get the char and place that in the array which is nothing but 
                                // placing it in the employees[i].Name. no dont need to return this 
                                // this value as it been sent using call by refernce method.
        array[z] = letter;
        ++ z;
    } while(letter != '\n' && z < strlen(array));   // included boundary checking  
    
    buffer[z-1] = '\0';  // Sepcify end of the string
    
    /* note no values returned */
}

U got messed up with the sentence function. If u wanted to get multiple input its all do to in the main not in the function sentence.

U'r for loop is wrong

Code:

for( i = 0; i > num; ++ i)

to 

for(i=0; i < num; i++)

sshaish2005

i call it by reference but i get an error saying
35 C:\Documents and Settings\Valued Customer\My Documents\project file\lab.c [Warning] passing arg 1 of `sentence' makes pointer from integer without a cast
for each time i put employees.etc into the sentence...

Code:

#include <stdio.h>

struct info
{
char Name;
char address;
float SS;
int age;
char gender;
char statues;
};

void sentence(char array[]);
void clear_buffer(void);

int main(void)
{
    struct info employees[10];
    int i=0,num;

    printf("How many employees you wish to log?\n");
    scanf("%d",&num); /* u need to give the address of num variable hence &num*/
    clear_buffer();
    
    if(num > 10)
    {
        while( num < 10 ) {
        printf("Error only up to 10\n");
        printf("How many employees you wish to log?\n");
        scanf("%d",&num); /* u need to give the address of num variable hence &num*/
 		     }
    }
    for( i = 0; i < num; ++ i)
    printf("what are the employees names?\n");
    sentence(employees[i].Name); /* Look at your function prototype it dosn't take 3 parameter */

    printf("What are the addresses?\n");
    sentence(employees[i].address);
    
    printf("What is there sex?\n");
    sentence(employees[i].gender);

    printf("is the employees marry or single?\n");
    sentence(employees[i].statues);
    
    printf("What is employees ages?\n");
    scanf("%d",&employees[i].age);
        
    printf("What is employees social security\n");
    scanf("%f",&employees[i].SS);

   
    return 0;
}


void sentence(char array[])
{
  int  z=0;   // count variable
  char letter;   // Letter used to hold char which is read from the user
  
    do 
    {    
        letter = getchar();   // get the char and place that in the array which is nothing but 
                                // placing it in the employees[i].Name. no dont need to return this 
                                // this value as it been sent using call by refernce method.
        array[z] = letter;
        ++ z;
    } while(letter != '\n' && z < strlen(array));   // included boundary checking  
    
    array[z-1] = '\0';  // Sepcify end of the string
    
    /* note no values returned */
}


void clear_buffer(void)
{
    int ch;
    while((ch=getchar())!='\n');
}

Originally Posted by Darkinyuasha1

i call it by reference but i get an error saying
35 C:\Documents and Settings\Valued Customer\My Documents\project file\lab.c [Warning] passing arg 1 of `sentence' makes pointer from integer without a cast
for each time i put employees.etc into the sentence...

Code:

#include <stdio.h>

struct info
{
char Name;
char address;
float SS;
int age;
char gender;
char statues;
};

void sentence(char array[]);
void clear_buffer(void);

int main(void)
{
    struct info employees[10];
    int i=0,num;

    printf("How many employees you wish to log?\n");
    scanf("%d",&num); /* u need to give the address of num variable hence &num*/
    clear_buffer();
    
    if(num > 10)
    {
        while( num < 10 ) {
        printf("Error only up to 10\n");
        printf("How many employees you wish to log?\n");
        scanf("%d",&num); /* u need to give the address of num variable hence &num*/
 		     }
    }
    for( i = 0; i < num; ++ i)
    printf("what are the employees names?\n");
    sentence(employees[i].Name); /* Look at your function prototype it dosn't take 3 parameter */

    printf("What are the addresses?\n");
    sentence(employees[i].address);
    
    printf("What is there sex?\n");
    sentence(employees[i].gender);

    printf("is the employees marry or single?\n");
    sentence(employees[i].statues);
    
    printf("What is employees ages?\n");
    scanf("%d",&employees[i].age);
        
    printf("What is employees social security\n");
    scanf("%f",&employees[i].SS);

   
    return 0;
}


void sentence(char array[])
{
  int  z=0;   // count variable
  char letter;   // Letter used to hold char which is read from the user
  
    do 
    {    
        letter = getchar();   // get the char and place that in the array which is nothing but 
                                // placing it in the employees[i].Name. no dont need to return this 
                                // this value as it been sent using call by refernce method.
        array[z] = letter;
        ++ z;
    } while(letter != '\n' && z < strlen(array));   // included boundary checking  
    
    array[z-1] = '\0';  // Sepcify end of the string
    
    /* note no values returned */
}


void clear_buffer(void)
{
    int ch;
    while((ch=getchar())!='\n');
}

you dint actually look at my code properly. Go through it again the answer is in there

ssharish2005

yea but even if i do that it would say the same thing

ooh i see i got an error -^^- forgot to put the braces for "for" heh