passing structure arrays to functions?

**bem82** · 10-29-2006

Hi, I have a fairly particular question and I couldn't find the answer in any of my books. I'm trying to pass a structure array to a function and I've chosen to access structure members via "->".

Ex:

Code:

 return_type function_name(struct X **ar)
     {
        for(i = 0; i < j; i++)
            .
            .
            ar[i]->member = x;
            .
            .
     }

Theres no problem compiling the interface file. However, I can't seem to pass the structure array to the function correctly in the main program. My syntax is incorrect. I know when passing a structure to a function we use the "&" to pass the address of the structure. But how would you pass a structure array to a function in main() so you can access structure members via ar[i]->member; ?

Thanks.

**nadroj** · 10-29-2006

since its an array i thought you just pass the name of the variable (no & needed). the datatype the array holds doesnt matter, its still an array... or so i thought.

**quzah** · 10-29-2006

Code:

void myfun( struct mystruct array[], size_t arraysize )
{
    size_t x;

    for( x = 0; x < arraysize )
    {
        printf("array[ %d ].something is %d\n", x, array[ x ].something );
    }
}
...
struct mystruct somearray[ SOMESIZE ];
...
myfun( somearray, SOMESIZE );
...

Like so.

Quzah.

**Salem** · 10-30-2006

Well that all depends on
- how you declare the variable in the calling function
- how you try and pass the variable in the calling function.

Given your code, then you would need something like

Code:

struct X *foo[10];  // or struct X **foo;
function_name( foo );

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