Thread: approximating euler's number

  1. #1
    Registered User
    Join Date
    Oct 2006

    approximating euler's number

    I am a newbie and I need some help with this one...

    e = 1 + 1/1! + 1/2! + 1/3! + 1/4! + 1/5! .......... 1/(n-1)! + 1/(n!)

    I need to approximate the euler's value, I want to know what should my for loop look like?

  2. #2
    Software Developer jverkoey's Avatar
    Join Date
    Feb 2003
    University of Waterloo
    Write it out as a summation and you're halfway there.

  3. #3
    Registered User
    Join Date
    Oct 2006
    This is what I have, but I am getting a logical error.
    n = getN();
                for (i = n; i > 0; i--)
                sum += (1/(float) i);
                printf( "Sum = %f\n", (sum + 1));
          return 0;
    Last edited by Salem; 10-26-2006 at 05:28 AM. Reason: Added code tags

  4. #4
    Its hard... But im here swgh's Avatar
    Join Date
    Apr 2005
    Please use code tags when you post code

  5. #5
    and the hat of int overfl Salem's Avatar
    Join Date
    Aug 2001
    The edge of the known universe
    > sum += (1/(float) i);
    You want something like
    sum += (1/ factorial(i) );

    Read the formula, then write the code.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  6. #6
    Fear the Reaper...
    Join Date
    Aug 2005
    Toronto, Ontario, Canada
    As a bookkeeping, I believe that e is actually known as Napier's constant. It was only named e in honor of Euler.
    Teacher: "You connect with Internet Explorer, but what is your browser? You know, Yahoo, Webcrawler...?" It's great to see the educational system moving in the right direction

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