Thread: nested loop, simple but i'm missing it

> while(scanf(" %c", &letter) != '.')
scanf returns the number of "conversions and assignments" or EOF
Which in this case gives you 0, 1 or EOF as possible results.
None of which are ever likely to be equal to '.'

Happy_Reaper's answer is pretty good.

If you're so intent on using scanf, you can try using :

Code:

while(scanf("%c",%letter) == 1 && letter != '.')
{
      //  Do loop as previously specified
}

I think that will work, as I believe statements in conditionals are evaluated left to right, but I don't know what the standard says about that.

Originally Posted by Happy_Reaper

If you're so intent on using scanf, you can try using :

Code:

while(scanf("%c",%letter) == 1 && letter != '.')
{
      //  Do loop as previously specified
}

I think that will work, as I believe statements in conditionals are evaluated left to right, but I don't know what the standard says about that.

It will work, but not because it's a conditional statement. Rather && is defined to be a sequence point, where the program will run the left side before the right side.

Other sequence points include || (OR), '?:'(tertiary conditionl operator),','(comma operator*), and ';'(technically not an opperator).

*Note that the comma is not an operator, and thus not a sequence point, when used in variable declaration and function calls. The most common use for the comma opperator is in the first line of a for loop.

Thank you for the specifictation.