Thread: fgets assigned to a char

Okay, so i have been writing a program, and to my joy i find i only have two warnings and no errors .

'' '=' char differs in levels of indirection from char * ''

here is the section of code where the error is:

Code:

			printf("\nHas the client claimed in the last 12 months? (Y or N):");

			fgets(cBuff02, sizeof(cBuff02), stdin);

			cAnsYN = fgets(cBuff02, sizeof(cBuff02), stdin);

			if (cBuff02[0] != '\n' && (*endptr == '\n' || *endptr == '\0'))
			{
				do
				{
					if (cAnsYN == 'Y')
					{
						iClaimNum++;

cAnsYN i declared as a char
cBuff02 i declared as a char array of size [BUFSIZ]
iClaimNum i declared as an int (but isnt relative to this problem)

Basically, its asking Y or N, if they put in Y, i want to be able to manipulate and use that data, as you can see where i assign the fgets part to cAnsYN, and where i write if(cAnsYN == 'Y').

Help much appreciated .

Keep in mind that fgets returns a pointer to the string it modified. This means that in order for

cAnsYN = fgets(cBuff02, sizeof(cBuff02), stdin);

to be a valid assignment, cAnsYN needs to be decared as a pointer to char.

>> && (*endptr == '\n' || *endptr == '\0')
>Where'd this come from?

I thought i had to do that to check that the last piece of data is either pressing enter or end of array bits? Can i not use this method to stop an error occuring incase they put in more string than my BUFSIZ?

EDIT: LOL, it seems when i pasted the do while loop from elsewhere in my program i added the part i needed for strtol by accident! 00ps.