strcat() added an unnecessary colon
I have these two lines of code within my program and the output I would hope to get would be: \927\Code:*txt_ptr++ = '\\'; *txt_ptr++ = (char)strcat(txt_ptr, "\\927\\");
However, the output I get after the second line is: \:927\
Where did the colon come from and how do I prevent it from getting there? Thanks!
Need more code. . . What are you trying to do?
I just want my output to be \927\ rather than \:927\
I'll try to get all the code that has to do with the output...unfortunately there's a lot of code that I have to sort through to figure out what is relevant...
Well try removing the cast, then reading the manual page for what strcat actually does.
Simply casting away all the warnings, then complaining about it not working is just dumb.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
You're casting an address, which is a hex value, as a character and assigning it's value to memory. Do you know what happens when you cast a hex value as a character and assign it to memory? You get a character, and since you really don't know what that address you casted was, you're getting a random character, which in this case appears to be a colon.Don't assign the result of strcat... and also, don't use strcat unless you're sure that your string is all NULLs, you could just being concatenating to the end of garbage.Code:Now when you have this: \\927\ and you assign a colon here v \\927\ Guess what you get.
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> and the output I would hope to get would be: \927\
Well the first line is useless, and the first half of the 2nd line is useless as well.
All you need is strcat(txt_ptr, "\\927\\");
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
