Thread: Confused Reading Command Line Argements

I'm using Windows XP and Visual Studio 200.

I have a command line program named test1. There are three arguments that are passed to it:
1. Name of the program
2. Input 1 (SMILES String)
3. Input 2 (fragment)

I figured out how to get/print the first letter from each argument:

Code:

#include <stdio.h>
#include "stdafx.h"


int _tmain(int argc, _TCHAR* argv[])
{
	int i;
	int correctParams = 1;

	if ( argc != 3 ) {
		printf( "Enter a Smiles string and fragment your searching for\n" );     
		correctParams = 0;
	}
	if (correctParams == 1) {

		for (i = 0; i < argc; i++)
			if (i == 2) {
			printf("argv[%d] = \"%s\"\n", i, argv[i]);
			}

	}

	return 0;
}

I'm wandering how you get all of the letters (argv[something?]. Basically, I would like to set the 3 different arguments to 3 different variables

Thanks King Mir.

For some reason, the program errors on strlen, its saying identifier not found:

Here's what I've changed my code to:

Code:

#include <stdio.h>
#include <string.h>
#include "stdafx.h"


int _tmain(int argc, _TCHAR* argv[])
{
	int i;
	int correctParams = 1;
	int length;
	char *arg1;

	if ( argc != 3 ) {
		printf( "Enter a Smiles string and fragment your searching for\n" );     
		correctParams = 0;
	}
	if (correctParams == 1) {

		length=strlen(argv[1]);

	}

	return 0;
}