Thread: pointers problem

hi all...

learning c pointers. i have this code :

PHP Code:

#include <stdio.h>
int main ()  {
        char string3[10], string4[] = "foo moo loo";

        for(; (*string3 = *string4) != '\0'; string3++,string4++)
                ;
return 0;
} 


the compiler returns:

strings.c: In function `main':
strings.c:25: error: wrong type argument to increment
strings.c:25: error: wrong type argument to increment
strings.c:25: warning: left-hand operand of comma expression has no effect
strings.c:25: warning: statement with no effect


what i don't understand is why the "wrong type argument to increment" error?
if the array name is also a pointer to the first element in the array and i'm using pointer aritmetic to move through the array/string why 'wrong type'?! isn't the address always an int?!

thanks....

Originally Posted by SlyMaelstrom

You can't increment an array name, it's illegal. The whole "array name is a pointer" is a common misconception. They aren't, in fact, the same thing. Assign the array names to a pointer and increment that.

thanks...

i'll use [code] next time... promise...

I spot an overflow.