Thread: obtaining a variable's address

hey all,
if I do something like this:

Code:

char buf[100], *p;
p = buf;

printf("%p\n", p);

that will print the address of the first element in buf (buf[0]), right? just making sure.


thanks in advance!

thanks fnoyan, tried this code and it prints "a":

Code:

#include <stdio.h>

int main(void)
{
	char buf[100], *p;
	p = buf;
	*p = 'a';

	printf(buf);

	return 0;
}

> tried this code and it prints "a":
Consider yourself somewhat lucky then.

There is no obvious sign of where the \0 to end the string came from

> printf(buf);
This is a really bad habit you need to get rid of.
Never pass user data as a format control string. Any % characters which get in there will cause you BIG problems.

really? I didn't know that . what can happen if I print a string containing format specifiers like that? not that I want to do it, I am just curious, since you said its a "really" bad habit.

http://en.wikipedia.org/wiki/Format_string_attacks