I would like to know how to get and/or change the memory address of e.g: "int i".
so if to say it is (hex): "22ff68" and i would like to change it to e.g (hex): "22ffa4"
how would i do that? -Btw i only know how to get the memory address of what addresses pointers has in their memory.

2. Well, your question is kind of wierd, but you might want pointer arithmetic.

http://c-faq.com/~scs/cclass/notes/sx10b.html
http://www.cs.umd.edu/class/spring20...p/pointer.html

Do you actually want 'i' to be somewhere else (why?) or do you just want to point to a different location?

3. Cause "int i"'s memory gets in the way, if i would like to have another variable's "int _4zz"
+1 in memory address so work you see, i want to use:
"*_4zz,(*_4zz+1),(*(_4zz+2),*(_4zz+3)"and so on..
But "int i" has the memory address of "(*_4zz+1)"so i would like to change it.
I dont want to stop using "*(_4zz+1)"cause it is good for looping e.g
Code:
`for(i=0;i<5;i++)printf("%d\n",*(_4zz+i);`
Now that i think more about it, i could change the pointer variable "*_4zz" memory address instaid maybe it would be easier (or just possible)?
Anyways... i think the solution would be pointers cause they handle memory addresses right?

Though it would be nice if i could just write it like this: &i = 22ff68, or &i = 2293608.
Like in "the memory address of 'int i' is equal to this"

4. Yes, that's called pointer arithmetic, good thinking. *(_4zz + i) is the same thing as the array notation _4zz[i], the c-faq explains that.