this is a simplified form of my question, if the user did not enter 'a' on the second if statement, will it go straight to else?Code:scanf ("%c", i); if (i=='a') { printf ("the user enterered a thus it entered if"); scanf ("%c", i); if (i=='a') { printf ("the user still entred a"); } } else printf ("the user did not enter a");
problem 1:
-scanf needs the address of 'a' as in &a
but to answer your question assuming the first line works... no
"You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter
Why not compile it and find out? No. The else binds to the first if.
Quzah.
Hope is the first step on the road to disappointment.
Consider the following code:
And see what the effect is .... enter every combination of a and something else and try to predict what the program will output.PHP Code:char c1, c2;
scanf("%c", &c1); /* Get a character */
scanf("%c", &c2); /* Get another character */
if (c1 == 'a')
{
printf("User entered an 'a' first ");
if (c2 == 'a')
{
printf("and also the second was an 'a'\n");
}
else
{
printf("buf the second was not an 'a'\n");
}
}
else
{
printf("First character was not an 'a' ");
if (c2 == 'a')
{
prinf("but the second one was!\n");
}
else
{
printf("and neither was the second one!\n");
}
}
I think you can put a signature here.
i'm sorry for the first one, forgot the & in there, yes i tried to compile it but the program just crash after i entered the character..
i already tried the code above, that was my original idea for my program but then it is a very long code..i'm trying to shorten my program now..
is my question above possible? like if the second if statement is false, it will do directly to the first else?
possible?
that's one way. Although its pretty silly at this pointCode:scanf ("%c", &i); if (i=='a') { printf ("the user enterered a thus it entered if"); scanf ("%c", &i); if (i=='a') printf ("the user still entred a"); } if(i!='a') printf ("the user did not enter a");
"You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter
by the way, thanks for all the peepz helping me out here..
here's the segment of the program i'm trying to do..
the else part, where the user stands, is quite long and putting the same code all over again when it's needed will make it long, so i thought if i'll put em in a nested if, i thought that anytime the if statements inside would return false, it will immediately go to this else, i was trying to make an else statement for multiple if's!Code:scanf ("%c", &cAction); if (cAction=='H' || cAction=='h') //if hte player hits { //codes to deal the third card from the player.. scanf ("%c", &cAction); if (cAction=='H' || cAction=='h') { //codes to deal the fourth card.. } } else //meaning if the user choose to stand.. {// codes to when the user stands.. }
this is a blackjack game by the way..
i cant use fuctions, it's hard to explain..
what do i do?
edit:
scratch that. I mentioned switch, but I forgot about the original requirement that it asks twice.
my thought would be to loop.
for(i=0; i < 2 && (a == 'H' || a == 'h'); i++).....
and then instead of the else, check for the condition (a == 'H' || a == 'h') in an 'if'
Last edited by FillYourBrain; 07-26-2006 at 08:10 AM.
"You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter
