2 to the power 5 (SIMPLE)

[Unregistered]

Here is some very simple code, which will not compile, can anyone tell me what the problem is and how to fix it?

#include <stdio.h>

int main()
{
float test;

test = 2;
test = test^5; /* This line is the problem */

printf("2^5 = %f\n", test);

return 0;
}

When I try to compile this using gcc I get the error:
test.c: In function 'main':
test.c:8: invalid operands to binary ^

Thankyou for helping

[Shiro]

The ^-operator is not the power operator. As far as i know, C doesn't have such an operator. So you'll have to implement a function by your self.

For example:

/* z = x ^ y = e ^ (y * ln (x)) */
z = exp (y * log (x));

Or:

int pow (int x, int y)
{
if (y == 1)
return x;
else
return (x * pow (x, y - 1));
}

[GaPe]

If you want to use "pow();" function you must use the "math.h" library.

[Unregistered]

Thankyou