Chars

**GaPe** · 01-01-2002

My program:

Code:

int main()
{
   char string[100];
   int i=0, j=0, NoLetter[25];

   clrscr();
   printf("Enter string: ");
   scanf("%s", string);
   do
   {
      for (j=97; j<=122; j++)
      {
         if (string[i] == j)
         {
            NoLetter[j-97]++;
            printf("\nString contains %d \"%c\"", NoLetter[j-97], string[i]);
         }
      }
   } while (string[i++] != '\0');
   getch();
   return 0;
}

The problem is the output:

Enter string: hello

String contains 1 "h"
String contains 1 "e"
String contains 1 "l" <- this I do not want to print it on the screen
String contains 2 "l"
String contains 1 "o"

I know that this prints out beacuse it is in the loop. I tried various ways, but none worked out.

Please help.

**Salem** · 01-01-2002

How about

Code:

#include <stdio.h>

int main()
{
    char string[100];
    int i=0, j=0, NoLetter[26] = { 0 };  // in my alphabet at least

    printf("Enter string: ");
    scanf("%s", string);

    for ( i = 0 ; string[i] != '\0' ; i++ ) {
        NoLetter[ string[i] - 'a' ]++;
    }

    for ( j = 'a' ; j <= 'z' ; j++ ) {
        if ( NoLetter[j-'a'] != 0 ) {
            printf("\nString contains %d \"%c\"", NoLetter[j-'a'], j );
        }
    }
    return 0;
}

**GaPe** · 01-01-2002

Thank you Salem.

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