Actually, I had to repost.
The little asterisk trick doesn't seem to work with brackets, so just use the number that BUFSIZ equals.Code:int foo, bar; char string[BUFSIZ], matchme[]="10,4,\"Foo'd up beyond all repair\",h\n"; sscanf(matchme, "%d,%d,%512[^\n]", &foo, &bar, string); printf("%d %d %s\n", foo, bar, string);
EDIT: OK, did it again.I mistyped the nul character. Sorry. That really does work, if you don't want to read to a flag character instead.
Last edited by whiteflags; 05-09-2006 at 02:57 PM.
You can use an extra variable to read anything past the last
character then if you don't a return code of 4 there was an error.
I think thats the simplest way to do it.
PHP Code:#include <stdio.h>
#include <string.h>
main(argc,argv)
int argc;
char *argv[];
{
int num, num2;
char matchme[]="1,5,\"some text\",h\n";
char str[40];
char ch[3], endchars[100];
if (sscanf(matchme, "%d,%d,%[^,],%1[hv]%[^\n]", &num,
&num2, str, ch, endchars ) != 4)
printf("Error reading string 1.\n");
else
printf("%d %d %s %s\n", num, num2, str, ch);
}/*main */
> If only there was perl compatible regular expressions included in the standard C.
Do you have some objection to linking with a library which does the same?
http://www.pcre.org/
> 1,5,"some text",h
Is this also an example (comma in the quotes)?
1,5,"maybe this, maybe that",h
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
