Thread: Problems reading formatted input with sscanf

  1. #16
    Lurking whiteflags's Avatar
    Join Date
    Apr 2006
    United States
    Actually, I had to repost.
        int foo, bar;
        char string[BUFSIZ], matchme[]="10,4,\"Foo'd up beyond all repair\",h\n";
        sscanf(matchme, "%d,%d,%512[^\n]", &foo, &bar, string);
        printf("%d %d %s\n", foo, bar, string);
    The little asterisk trick doesn't seem to work with brackets, so just use the number that BUFSIZ equals.

    EDIT: OK, did it again. I mistyped the nul character. Sorry. That really does work, if you don't want to read to a flag character instead.
    Last edited by whiteflags; 05-09-2006 at 02:57 PM.

  2. #17
    Fountain of knowledge.
    Join Date
    May 2006
    You can use an extra variable to read anything past the last
    character then if you don't a return code of 4 there was an error.
    I think thats the simplest way to do it.

    PHP Code:
    #include <stdio.h>
    #include <string.h>

    int  argc;
    char *argv[]; 
    int numnum2;
    char matchme[]="1,5,\"some text\",h\n";
    char str[40];
    char ch[3], endchars[100];
      if (
    sscanf(matchme"%d,%d,%[^,],%1[hv]%[^\n]", &num

    num2strchendchars ) != 4)
    printf("Error reading string 1.\n");
    printf("%d %d %s %s\n"numnum2strch);

    /*main */ 

  3. #18
    and the hat of int overfl Salem's Avatar
    Join Date
    Aug 2001
    The edge of the known universe
    > If only there was perl compatible regular expressions included in the standard C.
    Do you have some objection to linking with a library which does the same?

    > 1,5,"some text",h
    Is this also an example (comma in the quotes)?
    1,5,"maybe this, maybe that",h
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

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