Hi, i wanna know how to tokenize the string out of delimeter('--').For example:
aaa bbb-ccc -- eee fff ggg
The question i want to ask is, i want to token the word aaa bbb-ccc out, but
i am having trouble it give me (aaa bbb) not (aaa bbb-ccc), i know the problem is because
when it met '--' even is '-' it also token it out..Can i have any tips on this? Thanks.
Post the code you've written so far so we can help you further.
Good class architecture is not like a Swiss Army Knife; it should be more like a well balanced throwing knife.
- Mike McShaffry
Sorry bout that..
Here is part of my code
For Example:Code:while (fgets(read_line, 100, in) != NULL) { for (i=0; i<strlen(read_line); i++) { /* i think my logic here is wrong */ if ((read_line[i] == '-') && (read_line[i+1] == '-')) { ptr = strtok(read_line, "--"); } } ptr = strtok(read_line, "\n"); while(ptr != NULL) { strcpy(line, ptr); fprintf(out, "%s\n", line); ptr = strtok(NULL, "\n"); } }
Read in input are:
abc abc-abb -- bbb aaa eee
Output should be:
abc abc-abb
but my output is:
abc abc
There is a much cleaner, nicer way of doing this but I never pass up a chance to do some good ol' fashioned useless string hacking
Output:Code:int main(int argc, char *argv[]) { char str[] = "abc abc-bbb -- bbb aaa eee"; char* dst = new char[20]; char* p = &str[0]; char* d = &dst[0]; memset(dst, 0, 20); while (*p != '-') *d++ = *p++; while (*p != 32) *d++ = *p++; while (*p != 'b') p++; *d = 0; std::cout << "tokens:\n" << p << "\n" << dst << std::endl; return 0; }
EDIT: Damn this the C board. Can we just ignore the 'std::cout' - I can't be bothered to change itCode:tokens: bbb aaa eee abc abc-bbb Press any key to continue
I also realise my method is too problem-specific and relies on the user entering that exact string of characters.
Last edited by cboard_member; 05-03-2006 at 05:33 AM.
Good class architecture is not like a Swiss Army Knife; it should be more like a well balanced throwing knife.
- Mike McShaffry
Ok..i will try it out..thanks
Another way:
Code:#include <stdio.h> #include <string.h> int main(void) { const char text[] = "abc abc-abb -- bbb aaa eee"; char desired[32], *found = strstr(text, " --"); if ( found ) { sprintf(desired, "%.*s", found - text, text); printf("desired = \"%s\"\n", desired); } return 0; } /* my output desired = "abc abc-abb" */
7. It is easier to write an incorrect program than understand a correct one.
40. There are two ways to write error-free programs; only the third one works.*
