printing hex

[axr0284]

Hi,
I have a weird problem when printing hex values.

#include <sys/types.h>
#include <sys/stat.h>
#include <sys/mman.h> /* mmap() is defined in this header */
#include <fcntl.h>
#include <stdio.h>

int main (int argc, char *argv[])
{
 int fdin, fdout;
 char *src, *dst;
 struct stat statbuf;

 if (argc != 3) {
   printf("usage: a.out <fromfile> <tofile>");
   exit(1);
 }

 /* open the input file */
 if ((fdin = open (argv[1], O_RDONLY)) < 0)
   printf("can't open %s for reading", argv[1]);

 /* open/create the output file */
 if ((fdout = open (argv[2], O_RDWR | O_CREAT | O_TRUNC)) <
0)
   printf("can't create %s for writing", argv[2]);

 /* find size of input file */
 if (fstat (fdin,&statbuf) < 0)
   printf("fstat error");

/* go to the location corresponding to the last byte */
 if (lseek (fdout, statbuf.st_size - 1, SEEK_SET) == -1)
   printf("lseek error");

 /* write a dummy byte at the last location */
 if (write (fdout, "a", 1) != 1)
   printf("write error");

/* mmap the input file */
 if ((src =(char *) mmap (0, statbuf.st_size, PROT_READ, MAP_SHARED,
fdin, 0)) == MAP_FAILED)
   printf("mmap error for input");


 /* mmap the output file */
 if ((dst =(char *) mmap (0, statbuf.st_size, PROT_READ |
PROT_WRITE,MAP_SHARED, fdout, 0)) == MAP_FAILED)
   printf("mmap error for output");

printf("Data: %x\n",src[0]);
 /* this copies the input file to the output file */
 memcpy(dst, src, statbuf.st_size);

}

The file that I use is a binary file containing the following:
39 8e e3 38 8e 03 67 c0 c7 71 1c c7 71 1c 68

when I do the printf at the end, I get Data: 38e38e39

I would like it to print only 39 though and not the rest. Any idea how to do that. Thanks
Amish

[valis]

Will simply masking off the other bytes suffice? src[0] & 0x000000ff

[axr0284]

Sweet that does the trick. Thanks a lot,
Amish