Thread: accessing variables using structs

Hey guys how would i go about accessing a variable from the item
struct such as itemID how do i access it?

Code:

typedef struct category* CategoryTypePtr;
typedef struct item* ItemTypePtr;

/* Structure definitions. */
typedef struct price
{
   unsigned dollars;
   unsigned cents;
} PriceType;

typedef struct item
{
   char itemID[ID_LEN + 1];
   char itemName[MAX_NAME_LEN + 1];
   PriceType prices[NUM_PRICES];
   char itemDescription[MAX_DESC_LEN];
   ItemTypePtr nextItem;
} ItemType;

typedef struct category
{
   char categoryID[ID_LEN + 1];
   char categoryName[MAX_NAME_LEN + 1];
   char drinkType;      /* (H)ot or (C)old. */
   char categoryDescription[MAX_DESC_LEN];
   CategoryTypePtr nextCategory;
   ItemTypePtr headItem;
   unsigned numItems;
} CategoryType;

typedef struct gjc
{
   CategoryTypePtr headCategory;
   unsigned numCategories;
} GJCType;

would it still work if i go

Code:

GJCType new;
char * dtype;

strcpy(new->headCategory.drinkType, dType);

so copy the dType char * into the struct would that work

Guys Guys Guys

I can't understand what's going on in your conversation ? The original poster of the code asked how to access the variables of an array but you guys are discussing something else.

For the sake of the original poster i just wanna say that to access the variables of structure use "." operator try the following code:

Code:

#include<stdio.h>
#include<conio.h>

typedef struct item
{
   int a;
   float b;
}ITEM;

ITEM var;
int main()
{
      
     clrscr();
     printf("\n Enter first variable\t");
     scanf("%d",&var.a);
     printf("\n Enter second variable\t");
     scanf("%f",&var.b);
     printf("\n first value is %d",var.a);
     printf("\n second value is %f",var.b);
     getch();
     return 0;
}

OUTPUT:

Enter first variable      25
Enter second variable      62.5

first value is     25
second value is     62.500000

I hope you got it. IF you wanna access variables by using pointers then use "->" operator.



REALNAPSTER