Thread: Printing part of a string

Hi,

I've a string str as:

HiHello

I want to print only the Hello part i.e. from index 2 till the end like
print(str[3...endofstr]

How can I do that?

Thanks,
Angkar

Code:

for ( i = 2; i <= strlen( str ); i++ )
{
printf("%c", str[i] );
}

That should do the trick.

p.s. sorry about the lack of tabs in my code

And what if I want to store the string str[3...endofstr] in some other variable?

Or you could make:

Code:

{
   strncpy(str2,&str1[2],str2_size);
}

Or you could do something like this.

Code:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main(int argc, char **argv) {
    if(argc !=2)
        exit(1);

    char temp[]="Hello";

    size_t len_temp = strlen(temp);
    size_t len_argv = strlen(argv[1]);
    size_t len_diff = len_argv - len_temp;

    if(len_diff != 2)
        exit(1);

    if( strstr(argv[1],temp) )
        printf("%s\n",temp);

    return 0;
}

$gcc -Wall match.c -o match
$./match HiHello
Hello
$./match MeHello
Hello
$./match NoooHello
$./match Hello
$./match ribbit
$./match Hell
$

Of course, the code is case sensitive.

Thanks to CDALTEN as his example taught me new thing i.e. size_t . It's really cool to use it instead of making new charecter type arrays.



REALNAPSTER

Originally Posted by 00Sven

Code:

for( i=0, d=3; d < strlen( str ); i++,d++){
     str2[i]=str1[d];
}

~Sven

This will call strlen(str) for every iteration and so is much slower than if you only call strlen once.

Code:

int len = strlen(str);

for( i=0, d=3; d < len; i++,d++){
     str2[i]=str1[d];
}