This one seems easy, but I can't find a way to it. I'm scanning "m", which will tell me to type an integer "m" times, you put in the integers, and the end result should give me
printf("Enter an integer:\n");
else if (n>0)pluscountodd++;
else if (n<0)minuscounteven=-2;
else if (n<0)minuscountodd=-2;
, but with positive integers and not all zeros. I am able to do it if it's just positive or negative, but I don't know how to separate the odds and evens. I was hope that I could somehow start the odds at 1/-1, but I don't know if that's possible. Someone help! Much appreciated!
Among "m" scanned integers there are:
0 positive even and 0 positive odd integers,
0 negative even and 0 negative odd integers, and
0 zero integers.