I try something. But with small width there is something wrong, I cannot stop while loop. There is any other way to control my while loop?
Code:
#include <stdio.h>
#include <ctype.h>
#include <string.h>
void justifytext ( char *mytext, int width);
void justifyline ( char *line, int linewidth );
void main() {
char sstr[] = " ModelSim provides an Integrated Debug "
"Environment that facilitates efficient design debug "
"for SoC and FPGA based designs. This GUI has continuously "
"evolved to include new windows and support for new languages. "
"This application note aims to give an introduction to the "
"ModelSim 6.0 debug environment. This environment is "
"trilingual supporting designs based on VHDL, Verilog "
"(all standards including SystemVerilog, Verilog 2001 "
"and Verilog 1995), and SystemC. Subsequent releases of"
" ModelSim will enable even more debug capabilities "
"supporting higher levels of abstractions for verification"
" and modeling in SystemVerilog and SystemC. In ModelSim"
" 6.0, the GUI has been enhanced and is based on Multiple"
" Document Interface (MDI) layout standard. In addition, "
"the debug windows have been re-organized in such a way as"
" to display design data and simulation results in an intuitive manner.";
int twid;
int slen = 0;
slen = strlen(sstr); // Length of the input string
printf("\nLength of your text : %d\n", slen);
printf("Enter text width :");
scanf("%d",&twid);
printf("\nText Width %d\n",twid);
justifytext ( sstr, twid );
printf ("\n\n");
}
void justifytext ( char *mytext, int width){
char temp[100];//a string array for calling my second function
int i,j, currenti, counter = 0;
for ( i = 0; isspace(mytext[i]); i++ ); //if there is any space at the
memmove ( mytext, &mytext[i], strlen(mytext) );//beginning of the text, DELETED.
i = 0;
while ( counter < (int)strlen(mytext) ){//I choose such a control-loop, because I try
//some other ways and this is most trustable.
for ( i, j = 0; j < width; i++, j++ ){//finding each parts of text to justify
temp[j] = mytext[i];
}
for ( i ; !(isspace(mytext[i])); i--, j-- );//I cannot sperate any word,
//looking for spaces
currenti = i; //I will use it to start the next line
for ( i; isspace(mytext[i]); i--, j-- );//This makes part of array suitable
//for my second function.
counter = i; //for controlling loop //my second function works for only
//strings that do not have spaces
//neither at the begining nor at the end.
for ( ++j ; j < 100; j++ ) // only temp[++j] = '\0' is enough without for loop
temp[j] = '\0'; // but this makes me relax
justifyline ( temp, width );
i = currenti + 1; // this is where I start to sperate next time
}
}
void justifyline ( char *line, int linewidth )
{
char *temp; // it for usage of strtok function
int i, j, spaces = 0, spacestoshare=0, equalshare=0, extras=0;
for ( i = 0; line[i] != '\0'; i++ ){ //counting spaces. Also this means likely
//how many words there
if ( isspace ( line[i] ) ){
spaces++;
}
}
spacestoshare = linewidth - strlen(line);
if ( spaces == 0 ){
equalshare = spacestoshare+spaces; //if spaces zero, there is only a word means
extras = 0; // I put all my spaces after the word. No extras
}
else {
equalshare = (spacestoshare+spaces)/spaces;//How many spaces I will put between
//each word in equal
extras = spacestoshare % spaces; //Extra spaces to put
}
for ( temp = strtok ( line, " " ); temp != NULL; temp = strtok ( NULL, " ") ){ //takes
//each word sperately
printf ("%s", temp); //first write one word
for ( j = 0; j < equalshare; j++ ) { // add spaces after the word
putchar (' ');
}
if ( extras != 0 ){ // if there is extra
putchar (' '); //also add them
extras --;
}
}
putchar ('\n');
}
Originally Posted by a.baki
