I need some kind of brilliant insight into the code at the following URL
http://www.daniweb.com/code/snippet266.html
The question stems from mygeti() in the following code.
Code:
#include <stdio.h>
int mygeti(int *result)
{
char buff [ 13 ]; /* signed 32-bit value, extra room for '\n' and '\0' */
return fgets(buff, sizeof buff, stdin) && sscanf(buff, "%d", result) == 1;
}
int main(void)
{
int value;
do {
fputs("Enter an integer: ", stdout);
fflush(stdout);
} while ( !mygeti(&value) );
printf("value = %d\n", value);
return 0;
}
Isn't the line
A bit non-portable? What happens if the code was compiled under a 16 bit machine? Or more to the point, any type of machine who's int type is not 32 bit. Wouldn't the code break?
Originally Posted by cdalten
