Thread: Will not run.

Hi, I am fairly new to the c language and I am working on a project for my class. When I run this program in cmd prompt, and enter my menu selection, the program errors out on me.

Here is my code:

Code:

#include <stdio.h>


void DisplayMenu();
void Count10();
void Countby2();
void CountDown();
int main()
{
	void DisplayMenu();
	int menu;
	do
	{
		DisplayMenu();
printf ("Enter the number of the operatrion you would like to perform: ");
		scanf ("%d", menu);
		
		switch (menu)
		{
		case 1: Count10(); break;
		case 2:	Countby2(); break;
		case 3:	CountDown(); break;
		case 4:	printf ("Quitting the Program"); break;
		default : printf ("Invalid Input\n\n"); break;
		}
		
	}while (menu != 4);

	
	return 0;
}
//**************************************
//**************************************
void DisplayMenu()
{
	printf ("1. Count to 10\n");
	printf ("2. Count to 100 by 2\n");
	printf ("3. Countdown from 10\n");
	printf ("4. Exit\n");
}

//**************************************
//**************************************
void Count10()
{
int i;
	for(i=1;i<=10;i++)
	{
		printf ("%d", i);
	}
}

//*************************************
//*************************************
void Countby2()
{
	int i=0;
	while (i<=100)
	{
		printf ("%d\n", i);
		i+=2;
	}
}
//***********************************
//***********************************
void CountDown()
{
int f;
	for(f=10;f>0;f--)
	{
		printf ("%d\n", f);
	}

}

we havent learned most of that stuff u just said, we have been told to use scanf. Also, i stated that i was a noob so u dont need to be dick. if your going to be a dick, dont reply.

Quzah: The same thing also appears four lines above that snippet.

Vectorl33t: I'd love to know in what way I've offended. I neither poked fun nor swore at you, and I wrote the words "in future" for a reason, i.e. that you don't need/know fgets at the moment, but you will.

Allow me to explain: the need for the address of menu to be passed as an argument to scanf was the correct answer to the implied question "Why won't this run?". Hence, as many a game show host would say, "We have a winner", although they usually shout it in the manner I tried to convey.

I guess light-heartedness doesn't work here.

lol, tis hard to detect sarcasm over typing

ya, i got it running, now... i wanna run case 1 2 and 3 but this time with and inputting number from the user. So, what i did was add 3 new case statements. I cannot figure out how to run a loop with user inputted data, being i suck at programming. Here is what i added for one of my loops.

Code:

 
//*************************************
//*************************************
void Inputcountup()
{
int p;
int g;
	Printf ("Enter a number to count up to: ");
	scanf ("%d", &p);
		for(g=1;g<=p;g++)
{
			printf ("%d\n", g);
}

But when i run the program, it errors out again and says syntax error at the end of input. And i do not no what it means by this. and yes, before u ask i did include it at the top such as void inputcountup(); and it is also in my case statement and included in my menu as an option.

Here is all my code so far. And it tells me syntax error before ')' token on line 87.

Code:

#include <stdio.h>
//***************************
//***************************
void DisplayMenu();
void Count10();
void Countby2();
void CountDown();
void Inputcountup();
int main()
{
	void DisplayMenu();
	int menu;
	do
	{
		DisplayMenu();
		printf ("Enter the number of the operatrion you would like to perform: ");
		scanf ("%d", &menu);		
		switch (menu)
		{
		case 1 : Count10(); break;
		case 2 : Countby2(); break;
		case 3 : CountDown(); break;
		case 4 : Inputcountup(); break;	
		case 5 : printf ("Quitting the Program"); break;
		default : printf ("Invalid Input\n\n"); break;
		}
		
	}
		while (menu != 4);	
	return 0;
}
//**************************************
//**************************************
void DisplayMenu()
{
	printf ("1. Count to 10\n");
	printf ("2. Count to 100 by 2\n");
	printf ("3. Countdown from 10\n");
	printf ("4. Input Count up\n");
	printf ("5. Exit\n");
}

//**************************************
//**************************************
void Count10()
{
int i;
	for(i=1;i<=10;i++)
	{
		printf ("%d\n", i);
	}
}
//*************************************
//*************************************
void Countby2()
{
	int i=0;
	while (i<=100)
	{
		printf ("%d\n", i);
		i+=2;
	}
}
//***********************************
//***********************************
void CountDown()
{
int f;
	for(f=10;f>0;f--)
	{
		printf ("%d\n", f);
	}
	}
//***********************************
//***********************************
void Inputcountup()
{
int p;
int g;
	Printf ("Enter a number to count up to: ");
	scanf ("%d", &p);
		for(g=1;g<=p;g++)
{
			printf ("%d\n", g);
}
}
}

Remove a bracket at the end. If you had formatted correctly that would be readily apparent.

You will also need to decapitalize Printf in function Inputcountup