Thread: Small problem with printing elements of an array

i cahnged it around alot. Generally, if you have better format, the code is easier to understand. I was thinking about it, and what if you want to let the user enter a negative number? why dont you make a character array, and have one character that you enter to exit the loop?

Originally Posted by xixpsychoxix

i cahnged it around alot. Generally, if you have better format, the code is easier to understand. I was thinking about it, and what if you want to let the user enter a negative number? why dont you make a character array, and have one character that you enter to exit the loop?

i'm not too concerned about changing that right now, I just need to finish the assignment. I've added a couple things, but it still needs some more.

what i still have to do is :
Print out whether the first set entered by the user is a subset of the second
Print out the union and intersection of the two sets

...whatever that means. I'll be working on it for a while now.

Code:

#include <stdio.h>


void printset(int [] );   //function that prints the entered numbers in an array
void searcher(int [], int );  //function that prompts user to enter a number and searches set 1 for that number

int main()
{
	int i = 0, j = 0, srchlz, a[25] = {0}, b[25] = {0};

	printf("Choose some positive integers for set 1 (-1 to end set) :\n");
	for(i=0;i<25;i++)
	{
		scanf("%d",&a[i]);
		 if (a[i] == -1)
  {
   i = 25;
  }	


	
	}

	printf("Choose some more for set 2 (-1 etc):\n");
	for(j=0;j<25;j++)
	{
		scanf("%d",&b[j]);
		 
if (b[j] == -1)
  {
   j = 25;
  }	
	
	}




printf("Elements of set 1 are: \n");  
printset(a);								//run printset function for the first set of numbers


printf("Elements of set 2 are: \n");
printset(b);								//run printset function for second set 


printf("enter a number to search for in set 1:  ");
scanf("%d", &srchlz);
printf("\n");
searcher(a,srchlz);			//run function to search for user specified number in set 1



return 0;

}
	void printset(int c[])		//printing function
	{
		int k;
	printf("{");
	k = 0;
 for (k=0;k<25;k++)
 {
	if(c[k] != 0 && c[k] !=-1)
	printf("%d, ",c[k]);

	else if ( c[k] =-1)			//quit printing numbers when -1 is entered
	break;
	
	
	}
	
		printf(" }\n");
printf("the number of elements in this set is: %d\n",k);
	printf("\n\n");	
}

	void searcher(int d[], int srchlz)		///number searching function
	{
		int l;
		for(l=0;l<25;l++)
		{
		if (srchlz != d[l])
			continue;	
				
			
		else if (srchlz == d[l])
			
			printf("element %d is in set 1\n\n", srchlz);
			l = 25;												//function has found number in set, no need to search further
			
		}	

 if( l = 25 && srchlz != d[0])						//this is probably confusing, eh?
				printf("element %d is not in set 1\n\n", srchlz);			//function didn't locate the specified number
		

	}

apparently last night i changed it so you can enter negative numbers, but -1 to quit.

Code:

 if (a[i] == -1)
  {
   i = 25;
  }