Thread: passing array to function

Hi,
If I want to pass an array to a user-defined function, do I pass the array with it's index inside it,

Code:

int Func(int score[num_of_scores])

or do I have to pass the index separately?

Code:

int Func (int score[], int num_of_scores)

So thats all?

ok. I don't know if im doing this right. It compiles but comes out all wrong.

Code:

#include <stdio.h>
#define SIZE 5
void Func(int,int,int);

main()

{

	int array[SIZE] = {1,2,3,4,5},
		index=0,
		a=0;

		Func(index,array[SIZE],a);
		
}

void Func(int index,int array[SIZE],int a)

{

	for(index=0; index<5; ++index)
	{
		a = array[index];
		printf("\n%d" , a);
	}	
			
			

	
}

You dont need to use square brackets, or specify the size of the array when you pass an array, therefore:

Func(index,array[SIZE],a);

becomes

Func(index,array,a);

Originally Posted by Welshy

You dont need to use square brackets, or specify the size of the array when you pass an array, therefore:

Func(index,array[SIZE],a);

becomes

Func(index,array,a);

that is correct (you got it first Welschy )

also, you dont have to assign the number of elements of a unidimensional array when passing it to a function:

Code:

 void Func(int index,int array[SIZE],int a)

could be

Code:

 void Func(int index,int array[],int a)

I do get these warnings:

int ' differs in levels of indirection from 'int [5]' (line 13)
'Func' : different types for formal and actual parameter 2 (line 13)
formal parameter 2 different from declaration (line 19)

Originally Posted by SlyMaelstrom

Yes, it needs the brackets in the definition and prototype.

did you mean definition and declaration?

Ok. I've never seen that done before

Thanks that kills the warnings.