Thread: Finding the minimum value in an array?

Is there an easy way to find a minimum value in an array? Thanks.

Certainly,

1. Declare a variable (foo) to store the minimum.
2. foo = arr[0]
3. for every element in arr, if less than foo, assign foo to new value.

Code:

int min=0;


for (int i=0;i<iSizeOfArray;i++)
{
  if (i==0) 
     min=Array[i];
  else
    if (Array[i]<min) min=Array[i];
   
}

Thanks, sorry for not providing an example in C in the first place, I unrealistically expected them to try to learn things for themselves.

Thanks a lot. But I have another question. Is there a way to make it so that all the numbers will print out from smallest to largest? All that gives me is the smallest number every time.

Sort the array, then print it.
Search the board for lots of examples.

I checked, but still do not understand how to sort the array. Most examples have the array with numbers already entered, but in my program, the user enters up to 10 numbers, or presses 0 to quit. Any help? Here is my code:

Code:

#include <stdio.h>
#include <math.h>

#define Max_numbers 10




int main(void)

{        
         
         double x[Max_numbers],
                sum = 0,
                average;
             int y;   
         int i;
         int step = 1;
         char str[256];
         
         printf("Created by Matt Torsiello\n\n");

    printf( "Please enter your name:\t " );
    gets(str);
    printf("Hello, %s!\n", str);
    printf("Please Enter %d numbers separated by returns\n",
                   Max_numbers);
    for (i = 0; i < Max_numbers; ++i) {
        
       scanf("%lf", &x[i]); 
        if (x[i] == 0) {
                 y = i;
        i +=10; 
        step = 2; }
} 


 if (step == 2) {
          
          printf ("You entered %d numbers.\n", y);
          
      for (i = 0; i < y; ++i) {
          
          printf("\n%.2f", x[i]);    
          
          sum += x[i]; }

}

printf("\n\nThe total is %.2f.", sum);
average = sum / y;
printf("\nThe average is %.2f.", average);




system("Pause");
return (0);


}