Could someone give me some kind of technical explanation why the follow code will execute, but won't print anything out?
ThanksCode:#include <stdio.h> #include <signal.h> #include <unistd.h> static void sig_alarm(int signo) { if(signo == SIGALRM) printf("Signal Caught \n"); } unsigned int sleep1(unsigned int nsec){ if(signal(SIGALRM,sig_alarm) == SIG_ERR){ return(nsec); } alarm(nsec); pause(); return(alarm(0)); } int main(void) { sleep(5); return 0; }
Last edited by cdalten; 02-11-2006 at 06:53 AM.
Because you call the wrong sleep function
KurtCode:int main(void) { sleep1(5); // not sleep(5) return 0; }
you are not calling the fucntion properly. check out the code again. the main cals sleep fucntion. which seems to call sleep1 in your code.
ssharish2005
Yeah, sleep() is actually a function which causes the program to...for lack of a better word sleep, for 5 miliseconds or something or another....which is why the program compiled with no problems. Change the sleep() call in the main to sleep1() and you should be fine.
