string!

[rothj0hn]

nid help...

#include<stdio.h>
main()
{
chat num[4];
int a,b,c,d;
printf("input num");
scanf("%s",num);
a=num[0];
b=num[1];
c=num[2];
d=num[3];
printf("a=%d b=%d c=%d d=%d",a,b,c,d);
getch();
}

i simply input 1234
but i dont get the values of:
1 for a
2 for b
3 for c
4 for d
whats wrong w/ the program..
nid ur advice...

[caduardo21]

Try subtracting '0' from all the values in printf().
a - '0', b - '0', and so on...

[Salem]

> chat num[4];
This won't even compile.
Paste the code you compiled, not something you just "remembered".

Or even
a - 'a';

[rothj0hn]

typographical error.... chat is char.....

[Salem]

How can you make a typo, if you're supposed to be copy/pasting ?

If you're not accurately posting the code you're actually compiling, then it's a waste of time even to try and help you.

[CrazedBrit]

Why not simply do this?

#include<stdio.h>

int main()
{
char num[3];

printf("input num");
scanf("%s",&num);
printf("a=%c b=%c c=%c d=%c",num[0],num[1],num[2],num[3]);
getch();
return(0);
}

This way avoids the use of additional unneeded variables.

[quzah]

Well for starters, your array isn't big enough for what you're trying to do. For one thing, it's only 3 characters, which means there is no 'num[3]'. Furthermore, the spot 'num[2]' would be the null character, assuming you only typed 2 characters. The reason is you're using it like it's a string. In order to use it as if it were a string, you'd have to leave room for the null character. A string by definition is zero or more characters terminated by a null character.


Quzah.