Code:char a[10] = {0}; char a[10] = {0x0};
Code:char a[10] = {0}; char a[10] = {0x0};
There shouldn't be anything different between those two, I believe. You're just referring to the same thing using different base systems.
This is just a hunch, though.
Sent from my iPadŽ
Just as I thought:
0x0 is base 16 for 0
0 is base 10 for 0
