Thread: how to convert int to char

man sprintf

Lets take

Code:

 int dig = 123;

to convert it you should pic 3, 2 and 1 seperately. Using this

Code:

 

int countVar=dig;

for(int numOfDigits=0; countVar !=0;numOfDigits++) 
	countVar=countVar/10;
	
char char_array[100];  //Or you can use malloc(): char* char_array=(char*)malloc(numOfDigits+1);
	
for(int i=numOfDigits-1;i>=0;i--)
{
      char_array[numOfDigits-i-1]=char(dig%int(pow(10,(i+1)))/pow(10,i))+'0'; //Plus '0' to convert int to char
} 
char_array[numOfDigits]=NULL;

Tell me if it didn't work.

It's outdated C++ code on a C forum.

Originally Posted by Salem

Not to mention the rounding errors (and poor performance) when using pow()

No problem when base is 10.
>> It doesn't work
To make it work first it should be in C code not C++, second math.h should be included.

Before this poor thread acquires any further confusion,

Originally Posted by Dave_Sinkula

man sprintf

Code:

#include <stdio.h>

int main(void)
{
   char text[11];
   int value = 123;
   sprintf(text, "%d", value);
   printf("text = \"%s\"\n", text);
   return 0;
}

/* my output
text = "123"
*/