Thread: Have no idea (please help)

Code:

void fun1( void )
{
    while foo
    {
        fun2( );
        enter values
    }
}

Quzah.

You've not sufficiently described your problem. What Quzah suggests is a perfectly valid way of doing things, but may not be the solution to your problem. Describe your algorithm.

Remember that functions can be called multiple times with different arguments to get different results with no ill effects.

there are probably loads of ways to do that, namely just calling the functions in the right order in main, and about calling the fourth function in function 2, thats fine, but function definitions are always outside other functions. here's a program structure i came up with which may help you out:

Code:

#include <abunchofheaders.h>

void func1 ();
void func2 ();
void func3 ();
void func4 ();

int main ()
{
    func1 ();
    func2 (0);    /*this prevents calls to func4 before func3 has been executed*/
    func3 ();
    return 0;
}

void func1 ()
{
    /*some code*/
}

void func2 (int argument)
{
    /*some code*/
    
    if (argument == 1)
    {
       func4 ();
    }
    else
    {
        /*some more code*/
    }
}

void func3 ()
{
    /*some code*/
    func2 (1);   /*at the end of func3, call func2 like this*/
}

void func4 ()
{
    /*some code*/
}

;