Thread: return-type char

Could someone please illustrate a way to make a function that returns a string?

I was just wanting to test something simple below, a program that reads a string, and converts all the 's' to dollar signs. But I'm not sure how to make it return a string, and the program messes up when it runs and just exits out....

Code:

#include <stdio.h>    

char* conv(char *str);

int main()
{


      char string[256];

      char mstring[256]; // modified string

      printf("Enter a string:");

      fgets(string,sizeof(string),stdin);

     *mstring = conv(string);

     printf("%s", mstring);

     getchar();

      return 0;
}

char* conv(char *str) {
int lp;
char newchar;
    for (lp = 0; lp < str; lp++) {
          if (str[lp] == 's') { newchar = '$'; str[lp] = newchar; }
          }
          return *str;
}

Code:

#include <stdio.h>

void conv1 ( const char *str, char *newstr ) {
  int lp;
  char newchar;
  for (lp = 0; str[lp] != '\0' ; lp++) {
    if (str[lp] == 's') {
      newstr[lp] = '$';
    } else {
      newstr[lp] = str[lp];
    }
  }
  newstr[lp] = '\0';
}

char *conv2 ( char *str ) {
  int lp;
  char newchar;
  for (lp = 0; str[lp] != '\0' ; lp++) {
    if (str[lp] == 's') {
      str[lp] = '$';
    }
  }
  return str;
}

int main()
{
  char string[256];
  char *pstr;
  char mstring[256]; // modified string

  printf("Enter a string:");
  fgets(string,sizeof(string),stdin);

  // this doesn't modify the original copy
  conv1 ( string, mstring );
  printf( "Old=%sNew=%s", string, mstring );

  // this does
  pstr = conv2 ( string );
  printf( "Old=%sNew=%s", string, pstr );

  getchar();
  return 0;
}


$ ./a.out
Enter a string:this is a test
Old=this is a test
New=thi$ i$ a te$t
Old=thi$ i$ a te$t
New=thi$ i$ a te$t

Thanks Salem, your always helpfull, you truly are a God of the C

btw, things are rocking and rolling for me now, as I'm learning more, I've been creating my own functions, and doing more in C then I've ever been able to learn before, what an awesome language.