Thread: Passing function as an argument.

Hi!
There are two functions in my code:

Code:

void *memcpy(void *dest, const void *src, size_t n);
in_addr_t inet_addr(const char *cp);

I want to set IP address to an 4 element array in structure:

Code:

memcpy(arp->src_pr_addr, inet_addr("127.0.0.1"), 4);

But then I get an error:

arp_request.c:53: warning: passing arg 2 of `memcpy' makes pointer from integer without a cast

But when I define another variable and pass its address everything works:

Code:

long ip = inet_addr("127.0.0.1");
memcpy(arp->src_pr_addr, &ip, 4);

How can I pass function directly to memcpy(); functions second argument? Do I need some casting? Thank you!

You can't take the address of a return result - just use a temporary variable like you did in your last example.