initializing arrays with user input

[Unregistered]

My assignment is to ask the user what size array they want. The compiler keeps saying, constant expression required in function main().
code is:
cout<<"Enter size of array:"<<endl;
cin>>x;
int array1[x];

[GaPe]

I think this is not possible. You must define "char string[100];" and then you can enter how many arrays will you use.

[maes]

the only way for doing this is with dynamic memory allocation( I think).

char *string;

cout<<"Enter size of array:"<<endl; 
cin>>x; 
string= (char *) malloc(sizeof(char)*x);
...
...
...
free(string);//do not forget this, you have to free the memory

A better way of doing it is with "new" and "delete"
but I can't give you an example because I only use them 1 or 2.
look them up and use them instead of malloc

[Garfield]

You can use realloc. That way, you just realloc after every input.

[doubleanti]

your compiler might register memory frees as an atexit command... so check...

[Unregistered]

new and delete are C++ operators. This is the C board. also in C you do not need to cast malloc(), in fact it is better if you don't.
Furthermore, if you have GCC or a C99 compatible compiler you can use you original code.

[QuestionC]

Arrays must know how long they are at compile-time. If you want to allocate a certain amount of memory based on run-time information, you'll have to use dynamic memory allocation...

#include <stdlib.h>
int main ()
{
 int N;
 int * a;
 printf("Enter size of array: ");
 scanf ("%d", &N);
 a = malloc (sizeof(int) * size);
 // Now a is an array of N ints.
 return 0;
}

I am pretty sure this can be done with C++ arrays however, check their forum.