Originally Posted by mvd1212
Boy you guys are having a heckuva time with that one today...Code:char choice; ... scanf("%c", &choice );
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LMAO. I forgot the 'choice' in my smart ass reply and had to edit it in. But hey, I got the colored &.But in my defense, I have numerous alcoholic beverages as witnesses.
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Quzah.
Last edited by quzah; 12-02-2005 at 04:50 PM.
Hope is the first step on the road to disappointment.
Oops... I cut/pasted his code sample, then when I saw the %, I went in and edited it out. Yes, you need the & for a %c. I had considered suggesting that he do a %s, make choice an array, and useTyping as someone who's been coding in C since 1981 and has written more than one printf() implementation, I hang my head in shame at my omission.Code:while (choice[0] == 'y');
Insert obnoxious but pithy remark here
hehe... Yeah I didn't make that same mistake in the code.
I've tried to set choice = 'y' at the beginning of the code but it doesn't seem to do anything. I keep getting the problem that it'll print the message "Would you like to find another answer (y or n)? " and then it exits the code without waiting for input from the user.
I'm sorry if I'm making this difficult, I'm pretty new at this and if the option came at the beginning of the code then I could do it easily.
My instructor has just taught us about arrays and while she did say you could probably use them in this project, don't use them.
I thought there was some simple method to get the code to loop back that I was missing. Is it more complex then I imagined?
I'm not allowed to flush the input or use arrays. Not that I would know how to do that anyway.
