thanks for the help sunny n sly in the last post but salem locked it so i have to make a new one for the other problem... :/
it works, but how to i get it to tell them what age they r if its not 17 ?
ive got the name part to work just not the age, its annoying.
plz let me know, thanks.
I bet Salem would love to take you home and use you as target practice. You have like four other threads open in this forum less than a day old. STOP POSTING NEW ONES. I explained how to handle the name else statement. Age is no different.
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Well this posting frenzy must come from the name I suppose....
sorry for posting that many ill cut down heh.
but it is different as it doesnt work... ?
Code:the scanf( "%d" , age ); is right isnt it? if ( age == 17 ) { printf ( "im that age too\n" ); } else { printf ( "you are %d\n", age ); } this will not work it just says, you are and a double arrow char.
This symbol refers to the address of the variable. In the case of name, which is an array, the array name without an index already refers to the address.Code:scanf ( "%d", &age );
Last edited by SlyMaelstrom; 12-01-2005 at 12:04 PM.
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oh yeh i see sorry. i had the &name but i took it out because name didnt use one, didnt know arrays didnt need one. sorry.
thankyou.
geez it still wont work. if i type in the age part, 60 it gives
your age is 2293612
whats the problem cuz the code looks good to me.. then again im a n00b.
Oh that's my fault, copied the wrong line for the example.
The & sign goes on the scanf variable not the printf variable.
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