# Thread: Missing something in dayofweek program

1. ## Missing something in dayofweek program

I had to write a program that prompts the user for three integers representing the day, month, and year of a given date (e.g. 5 24 1994), and that displays the day of the week for the given date (e.g. 5/24/1994 is a Tuesday). Below is the pseudo-code. I wrote the program but I seem to be missing something. When I execute the program, and I enter say, "5 12 1981" , the result shows "3 12 1981" subtracting two from the month. Why am I getting the adjusted month in my results? Can someone tell me what I'm missing?

a) First, adjust the month and year:
move the month 2 places down; that is; if the month entered is not January or February, subtract 2 from it to get the adjusted month, and make the adjusted year the same as the given year;
if the month is January or February, the adjusted month is month 11 or 12 of the previous year, which is the adjusted year.

b) Second, compute a month correction M, which is (26 times the adjusted month) minus 2, divided by 10 (integer division).

c) Third, compute the century C (actually century minus 1) and year Y within the century for the adjusted year (so, for example, if the adjusted year is 1993, C will be 19 and Y will be 93).

d) Fourth, compute a year correction Z which is Y + (Y divided by 4) + (C divided by 4) + (5 times C).

Again, all division are integer divisions.

e) Finally, compute a code D for the day of the week for the given date. D is the remainder after division by 7 of the sum of the day, month correction M and year correction Z. Now, if D is 0, 1, 2, …6 then, the day of the week is Sunday, Monday, Tuesday, …, Saturday respectively.

Here is my code:

Code:
```#include <stdio.h>
#include <stdlib.h>

int main()
{
int day,month,year;
int M,C,Y,Z,D;
char more[2];

do

{
printf ("Enter the date: (mm dd yyyy)");
scanf ("%d %d %d",&month,&day,&year);

if (month > 2)
month -= 2;

else
{
month = 10 + month;
year --;
}

M = ((26*month)-2)/10;

C = year/100;

Y = year % 100;

Z = (Y)+(Y/4)+(C/4)+(Y*C);

D = (day+M+Z)%7;

if (D=0)

{
printf("%d/%d/%d is a Sunday\n",month,day,year);
}

else if (D=1)

{
printf("%d/%d/%d is a Monday\n",month,day,year);
}

else if (D=2)

{
printf("%d/%d/%d is a Tuesday\n",month,day,year);
}

else if (D=3)

{
printf("%d/%d/%d is a Wednesday\n",month,day,year);
}

else if (D=4)

{
printf("%d/%d/%d is a Thursday\n",month,day,year);
}

else if (D=5)

{
printf("%d/%d/%d is a Friday\n",month,day,year);
}

else if (D=6)

{
printf("%d/%d/%d is a Saturday\n",month,day,year);
}

printf ("Continue? (y/n):");
scanf ("%s",&more);

}

while (more [0] != 'n');
return 0;

}```

2. When I execute the program, and I enter say, "5 12 1981" , the result shows "3 12 1981" subtracting two from the month.
Well, that's the code you wrote.
Code:
```  if (month > 2)
month -= 2;

else
{
month = 10 + month;
year --;
}```
Perhaps you need another temporary variable, say m, to hold the (potentially modified) month.

This is assignment:
Code:
`else if (D=6)`
This is comparison:
Code:
`else if (D==6)`
Also, recheck this against your formula:
Code:
`Z = (Y)+(Y/4)+(C/4)+(Y*C);`

3. Code:
```    if (D=0)

{
printf("%d/%d/%d is a Sunday\n",month,day,year);
}

else if (D=1)

{
printf("%d/%d/%d is a Monday\n",month,day,year);
}

else if (D=2)

{
printf("%d/%d/%d is a Tuesday\n",month,day,year);
}

else if (D=3)

{
printf("%d/%d/%d is a Wednesday\n",month,day,year);
}

else if (D=4)

{
printf("%d/%d/%d is a Thursday\n",month,day,year);
}

else if (D=5)

{
printf("%d/%d/%d is a Friday\n",month,day,year);
}

else if (D=6)

{
printf("%d/%d/%d is a Saturday\n",month,day,year);
}```
Doesn't this look better?
Code:
```  char *days[] = { "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday",
"Friday", "Saturday" };

printf("%d/%d/%d is a %s\n",month,day,year,days[D]);```