Hello,
I think the title i snot the best. Here is my problem:
I now want to connect these both and want to create an array with 10 IntArray elements, where every IntArray has size 7. Is this possible?Code:IntArray v(7); // creates an integer array with size 7 IntArray v[10]; // creates an array with 10 elements where each element is an integer array (with size 0)
Best greetings and thanks for the help,
Dee
There is no such variable type as 'IntArray'. If you've typedef-ed one, then you need to show us what it is. If it's a macro, show that too. Otherwise, you're wrong on all accounts.
Quzah.
Hope is the first step on the road to disappointment.
Hello!
Unfortunately I think I've posted in the wrong board. It should be a C++ problem! Some mod may be so nice and move it please.
IntArray is just a class with something like int *A[]... only that the boundaries are checked before.
At the end I just want to have something like int *q[7][10] but with my IntArray.
Greetings,
Dee
Last edited by dee.dw; 10-26-2005 at 08:06 AM.
what is [b]???? Maybe its me but I don't get your post. if you want to set something like int q[7][10] through a constructor, pass it 2 integers and make those your indices. Some code would have helped wonders.
Code:class IntArray { public: IntArray(int a, int b); ~IntArray(); private: int* array; int rows; }; IntArray::IntArray(int a, int b) { array = new int[a][b]; rows = a; } IntArray::~IntArray() { for( int i=0; i<rows; i++ ) { if( array[i] ) { delete [] array[i]; array[i] = 0; } } delete [] array; } // always cleanup :)
Last edited by durban; 10-26-2005 at 06:57 AM.
-"What we wish, we readily believe, and what we ourselves think, we imagine others think also."PHP Code:sadf
I didn't even know C had constructors.
@durban: The [b] was vB-Code.Should be bold, but I correct it now... I hope the meaning is now a little bit clearer.
And you want code, so I post some:
Your code is good, I only thought that there is a solution in C or C++ that gives me the same with one line, because withCode:class IntArray { // IntArray public: IntArray(void); // standard constructor IntArray(const unsigned int l); // standard constructor private: int* values; // array of integer for values unsigned int length; // size of array }; IntArray::IntArray(void){ // standard constructor length=0; // set length of array for better indexing values=NULL; }; IntArray::IntArray(const unsigned int l){ // standard constructor length=l; // set length of array for better indexing if (length) { values=new int[l]; for (unsigned int i=0; i<length; i++) values[i]=0; } else values=NULL; }; IntArray::~IntArray() { // destructor if (values) delete[] values; // give memory free };my first constructor is called and set the length to 0.Code:IntArray v=IntArray[10]
So my question again: Is it possible to call the second constructor with a number l?
@Learner: As I said in my second post I've chosen the wrong message board.
Sorry for all the chaos...
Greetings, Dee
Ah, i think i see your problem. Unfortunately, 1 line obviously can't do this because you would want different l values for each IntArray right?
Try that codeCode:IntArray* v[10]; v[0] = new IntArray(5); v[1] = new IntArray(10); etc..
Last edited by durban; 10-26-2005 at 08:42 AM.
-"What we wish, we readily believe, and what we ourselves think, we imagine others think also."PHP Code:sadf
Different sizes in each entry as you said would be the next. And I think the only way to init these arrays is with a ingle initialisation as you mentioned it...
At this time I do it as:
But I thought you could it do shorter... Something likeCode:Int Array *v[10]; for (int i=0; i<10; i++) v[i]=new IntArray(5)that creates 10 IntArrays with size 5.Code:Int Array v(5)[10]
Greetings, Dee
