1. ## simplify this?

Code:
```#include <stdio.h>

void main()
{
int matrix[100][100], n, k, l, bord, bord1, bord2, bord3, bord4;

do{
printf("Enter order of matrix between 1 and 100 \n");
scanf("%d",&n);
}while(n<1 || n>100);

for(k=0;k<n;k++){
printf("Enter values for Row %d\n",k);
for(l=0;l<n;l++){
printf("Enter values for row %d col %d\n",k,l);
scanf("%d",&matrix[k][l]);
}
}
bord=0;
for(k=0;k<1;k++){
for(l=0;l<n;++l){
bord=bord+matrix[k][l];
}
}
bord1=0;
for(k=n-1;k<n;k++){
for(l=0;l<n;++l){
bord1=bord1+matrix[k][l];
}
}
bord2=0;
for(l=0;l<1;l++){
for(k=0;k<n;k++){
bord2=bord2+matrix[k][l];
}
}
bord3=0;
for(l=n-1;l<n;l++){
for(k=0;k<n;k++){
bord3=bord3+matrix[k][l];
}
}
bord4=0;
bord4=bord+bord1+bord2+bord3;
printf("The sum of the border elements are: %d\n",bord4);
}```
I'm supposed to make a square matrix n x n, and get the sum of all border elements. This program is what I came up with, it works well enough, I was just wondering if there was a way to use fewer iterative statements.

2. Forgetting the setup process, the addition of all the sides can be peformed using only one loop. For now, I'll leave it to you to figure out how

Also, are you sure your program does what you want? I entered a 2x2 matrix, each cell containing the value 1, and it told me the sum was 6:
Code:
```Enter order of matrix between 1 and 100
2
Enter values for Row 0
Enter values for row 0 col 0
1
Enter values for row 0 col 1
1
Enter values for Row 1
Enter values for row 1 col 0
1
Enter values for row 1 col 1
1
The sum of the border elements are: 6```

3. Code:
```bord2=0;
for(l=0;l<0;l++){ /*changed it to 1*/
for(k=0;k<n;k++){
bord2=bord2+matrix[k][l];```
Thanks.