Thread: Hex to binary conversion and storing in nybble

Originally Posted by quzah

First and foremost, main is not a void function. It returns an int always. Next, what exactly is that strcat trying to do? It's wrong, whatever it is.

You're looking for bit shifting. There's a FAQ on the topic.


Quzah.

hi, strcat was supposed to add the latest binary nybble that will have been masked beforehand. it should follow on from the section im actually enquiring about!!

sorry for confusing

thanks for the pointer

I do not understand the goal of your program but I think the following code could be useful to you:

Code:

#include <stdio.h>


int main()
{
	int Hex;

	printf("Please enter a number in hexadecimal Ex. A4  : ");
	scanf("%x", &Hex);

	printf("0x%X is equal to %d.\n", Hex, Hex);

	return 0;
}

My Output:

Please enter a number in hexadecimal Ex. A4 : 1F
0x1F is equal to 31

thanks brad, i managed to fix it with quzah's advice.

i have a new problem that, now i want to add the resultant strings together but strcat isnt working for me, it keeps saying it cant convert between unsigned char pointers and so on....

im using the following snippet of code but it gives me that error

Code:

unsigned char streaminput[300] = "53720caea0e9d080c8280821b775ca286094e9d0402c1bfc50d4fbd700";
unsigned char f;
unsigned char mybyte, mybyte1, nibble1, nibble2;
unsigned char decode[2];

char decoded[60];
unsigned int k,l; 


........



	k++;
	nibble2 = mybyte1;	

	decode[0] = nibble1 | nibble2;
	decode[1] = '\0';

	printf("%02x", decode[0]);

	strcat(decoded, (char *) decode);

	l++;
}
	printf("\n%02x\n", decoded);

thanks everyone, so far

strcat isn't the most spectacular tool for this job. Why don't you just assign decode[0] (nibble1 | nibble2) straight into decoded[offset], then when you're finished, terminate decoded with a null character ('\0').

Also, printf("%02x", decoded); makes no sense, decoded is a char array, perhaps you meant to iterate through it and show the hex value of each element? ie decoded[0], decoded[1], etc.?

If you want to print the whole string as hex values, you'll need a for loop, unless you want to do:

Code:

printf("%02x %02x %02x ...", decoded[0], decoded[1], decoded[2], ...);

Which is quite ridiculous.

Originally Posted by cwr

If you want to print the whole string as hex values, you'll need a for loop, unless you want to do:

Code:

printf("%02x %02x %02x ...", decoded[0], decoded[1], decoded[2], ...);

Which is quite ridiculous.

i'd say that was pretty ridiculous, even for me!!

i've gone for this approach so far, based on what you told me

Code:

	decode[0] = nibble1 | nibble2;
	decode[1] = '\0';

	decoded[l] = decode[0];

	printf("%02x", decode[0]);

	l++;
}
	printf("\n%x\n", decoded[0]);

here its obviously printing out the first address of decoded and gives me "53", whci his perfect as its now storing two of these chars in the one address.

thanks

Right, but you no longer need the decode array:

Code:

    decoded[l] = nibble1 | nibble2;
    printf("%02x", decoded[l]);
    l++;
}
printf("%x\n", decoded[0]);

Originally Posted by cwr

Right, but you no longer need the decode array:

Code:

    decoded[l] = nibble1 | nibble2;
    printf("%02x", decoded[l]);
    l++;
}
printf("%x\n", decoded[0]);

ahhh, yes!!

thanks alot.....

Originally Posted by shoobsie

ahhh, yes!!

thanks alot.....

one last question, when i try to print

Code:

 decode[6];

or something higher, it gives me freaky outputs like

0effff

or something.....

Originally Posted by cwr

Most likely because you are mixing signed or unsigned, or something. Show your full code, if it's not too long.

Edit: And I hope you mean decoded[6], not decode[6]? Have you got rid of the decode array?

yeah you were right!

decoded was a char instead of bieng unsigned!

thanks alot.