Greetings,
I am writing a program that based around the command line input of a phone number (numbers only).
I understand that the number will be stored in char *argv[].
(i.e. argv[1])
I want check each digit in the phone number. How would I go about doing this?
for example:
a simple piece of code that will print each digit to stdout would suffice
thank you for your time
If argv[1] is a string, then argv[1][i] may be a character in the string.Code:#include <stdio.h> int main (int argc, char *argv[]) { if ( argc > 1 ) { int i; for ( i = 0; argv[1][i]; ++i ) { printf("%c\n", argv[1][i]); } } return 0; }
7. It is easier to write an incorrect program than understand a correct one.
40. There are two ways to write error-free programs; only the third one works.*
sorry.... the PHONE NUMBER is an argument for the program
i.e.
programname 4588742
thank you
I tried that before but I put
Code:printf(argv[1][i]); // instead of printf("%c\n",argv[1][i]);
