Well Im suppose to write a program that models a simple calculator. I have made an attempt at it but I dont think I did it right. I also dont know how to add a function so it does the whole to the power thing. If anyone can help me it would mean a lot thnx. Also, I believe im suppose to give it a operator to quit the calculator; however, i have tried to make it to ask the user whether they want to do another problem. heres what i have:
Code:#include <stdio.h> /* provides standard functions */ /* Function prototypes */ void scan_data(int *num1, int *num2); /* Prototype 1 */ char do_next_op(void); /* Prototype 2 */ void print_number(int num); /* Prototype 3 */ int main(void) { int num1, num2; /* numbers used in the arithmetic */ char op; /* arithmetic operator + - * or / */ char again; /* yes or no depending on the user */ int ans; /* arithmetic answer */ /* solves arithmetic if user continues */ do { /*Gets simple arithmetic problem */ scan_data(&num1, &num2); op = do_next_op( ); scan_data(&num1, &num2); /* computes the result */ switch (op) { case '+': add_number(num1, num2, &ans); break; case '-': subt_number(num1, num2, &ans); break; case '*': mult_number(num1, num2, &ans); case '/': divd_number(num1, num2, &ans); break; } /* Displays problem and result */ printf(" %c ", op); print_number(num1, num2); printf(" = "); print_number(ans); /* ask about doing another problem */ printf("\nDo another problem? (y/n)> "); scanf(" %c ", &again); } while(again == 'y' || again == 'Y'); return (0); }
