Thread: warning C4047: '=' : 'int' differs in levels of indirection from 'int *__w64

I do not understand what this error message means.

What is wrong with this code?

Code:

int cio_edit(char *str, int row, int col, int flen, int slen,
                int *ins, int *curpos, int *spos, int isMultiLine)
{
    int ch, 
        insert = 1,
        cursorP = 0,
        offsetP = 0;

  
        if(*ins==NULL){*ins = &insert;}
       if(*curpos==NULL){*curpos = &cursorP;}
       if(*spos==NULL){*spos = &offsetP;} 

}

variable ins is a pointer. *ins is an integer. the code should be like this

Code:

if( ins == NULL)   ins = &insert;

variable ins is a pointer. *ins is an integer. the code should be like this

No it shouldn't. If he does it that way, then the value that ins points to goes out of scope once the function ends.

It should be:

Code:

if( ins == NULL)   *ins = insert;

And the same goes for the two other assignments in that function.

Originally Posted by bithub

No it shouldn't. If he does it that way, then the value that ins points to goes out of scope once the function ends.

It should be:

Code:

if( ins == NULL)   *ins = insert;

And the same goes for the two other assignments in that function.

Your code dereferences a null pointer.